//#include // use angled, so posix.h will vary depending of the platform #include // for abort #include // for size_t #include // for SIZE_T_MAX #include // for strlen definition #ifdef MAP_TO_EDK_STRLEN extern "C" UINTN EFIAPI AsciiStrLen(IN CONST CHAR8 *String); #endif // Hope that unsigned long long is as big in bits sa a pointer difference. #define DOWN_CAST_TO_SIZE_T(a) ( (uintptr_t)(a) > (uintptr_t)(SIZE_T_MAX) ? abort(), 0 : (size_t)(a) ) /* Return the length of the null-terminated string STR. Scan for the null terminator quickly by testing four bytes at a time. */ size_t strlen (const char *str) { #ifdef MAP_TO_EDK_STRLEN return (size_t)(AsciiStrLen(str)); #endif const char *char_ptr; const unsigned long int *longword_ptr; unsigned long int longword, himagic, lomagic; /* Handle the first few characters by reading one character at a time. Do this until CHAR_PTR is aligned on a longword boundary. */ for (char_ptr = str; ((uintptr_t) char_ptr & (sizeof (longword) - 1)) != 0; ++char_ptr) if (*char_ptr == '\0') { return DOWN_CAST_TO_SIZE_T(char_ptr - str); } /* All these elucidatory comments refer to 4-byte longwords, but the theory applies equally well to 8-byte longwords. */ longword_ptr = (unsigned long int *) char_ptr; /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits the "holes." Note that there is a hole just to the left of each byte, with an extra at the end: bits: 01111110 11111110 11111110 11111111 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD The 1-bits make sure that carries propagate to the next 0-bit. The 0-bits provide holes for carries to fall into. */ himagic = 0x80808080L; lomagic = 0x01010101L; if (sizeof (longword) > 4) { /* 64-bit version of the magic. */ /* Do the shift in two steps to avoid a warning if long has 32 bits. */ himagic = ((himagic << 16) << 16) | himagic; lomagic = ((lomagic << 16) << 16) | lomagic; } if (sizeof (longword) > 8) abort (); /* Instead of the traditional loop which tests each character, we will test a longword at a time. The tricky part is testing if *any of the four* bytes in the longword in question are zero. */ for (;;) { longword = *longword_ptr++; if (((longword - lomagic) & ~longword & himagic) != 0) { /* Which of the bytes was the zero? If none of them were, it was a misfire; continue the search. */ const char *cp = (const char *) (longword_ptr - 1); if (cp[0] == 0) return DOWN_CAST_TO_SIZE_T(cp - str); if (cp[1] == 0) return DOWN_CAST_TO_SIZE_T(cp - str + 1); if (cp[2] == 0) return DOWN_CAST_TO_SIZE_T(cp - str + 2); if (cp[3] == 0) return DOWN_CAST_TO_SIZE_T(cp - str + 3); if (sizeof (longword) > 4) { if (cp[4] == 0) return DOWN_CAST_TO_SIZE_T(cp - str + 4); if (cp[5] == 0) return DOWN_CAST_TO_SIZE_T(cp - str + 5); if (cp[6] == 0) return DOWN_CAST_TO_SIZE_T(cp - str + 6); if (cp[7] == 0) return DOWN_CAST_TO_SIZE_T(cp - str + 7); } } } }